Find the value of a2+b2+c2-ab-bc-ca. When a-b=2, b-c=3, and c-a=4.
Answers
Answered by
2
Step-by-step explanation:
a*2+b*2-ab-bc-ca+c*2
(a-b)*2+ab-bc-ca+c*2
4-b(c-a)+c(c-a)
4-(c-a)(b-c)
4-(4)(3)
4-12
-8
Similar questions