English, asked by gamitkain23, 5 months ago

Find the value of (a2+b2+c2), given that (a+b+c) = 129 and ab=2279, bc=1419, ac=1749.

Answers

Answered by computerscience19

3

Answer:

a2+b2+c2=18415

Explanation:

since a2+b2+c2=(a+b+c)2-2(ab-bc-ca)

= (129)2 -2(2279-1419-1749)

=16641-2(-889)

=16641+1778

a2+b2+c2 =18415

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