Math, asked by trusfratted7, 3 months ago

find the value of a³+ 3a²b + 3ab + b³ if a = -2 , b=3
with steps​

Answers

Answered by satyamsingh02003
1

Ans:-Given:-

= a³+ 3a²b + 3ab + b³

= a = -2 and b = 3

Solution:-

we know that,

a³+ 3a²b + 3ab + b³ = (a+b)³

Now,

= (a + b)³

= (-2+3)³

= (1)³

= 1

here is your answer

hope it will help you

Answered by garvit2375
14

Answer:

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