find the value of a³+ 3a²b + 3ab + b³ if a = -2 , b=3
with steps
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Ans:-Given:-
= a³+ 3a²b + 3ab + b³
= a = -2 and b = 3
Solution:-
we know that,
a³+ 3a²b + 3ab + b³ = (a+b)³
Now,
= (a + b)³
= (-2+3)³
= (1)³
= 1
here is your answer
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