Question

find the value of a3 _ 3a2b +3ab2_ b3 where a=2 and b= 4​

Answer 1

Answer:

-56

Step-by-step explanation:

8-9*16+9*16-64

= 8-144+144-64

= -56

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Answer 2

Answer:

$a {}^{3} - 3a {}^{2} b + 3ab {}^{2} - b {}^{3 } \\ given \: \: a = 2 \: \: \: b = 4 \\ = 2 {}^{3} - 3 \times 2 {}^{2} \times 4 + 3 \times 2 \times 4 {}^{2} - 4 {}^{3 } \\ = 8 - 48 + 96 - 64 \\ = 104 - 112 \\ = - 8$