Question

find the value of a³+b³-3 abc, given that a=3, b=2, and c=1​

Answer 1

Step-by-step explanation:

a=3,b=2 and c=1

so.....

a^3 will be 3^3 which is 27

b^3 will be 2^3 which is 8

hence equation now is,

27+8-3 which is 27+5 = 32

hope it helps:)

Answer 2

To Find :

• Value of a³ + b³ - 3abc

Solution :

• a = 3
• b = 2
• c = 1

a³ + b³ - 3abc .....1)

substituting values of a ,b and c in 1)

= a³ + b³ - 3abc

= 3³ + 2³ - 3 × 3 × 2 × 1

= 27 + 8 - 18

= 35 - 18

= 17

Hence,

• value of a³ + b³ - 3abc is 17

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