Find the value of a³+b³+6ab-8 when a+b=2
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Answered by
34
a3+b3+6ab-8= (a+b)3-3ab(a+b)+6ab-8
=(2)3-3ab*2+6ab-8
=8-6ab+6ab-8
=0
=(2)3-3ab*2+6ab-8
=8-6ab+6ab-8
=0
Answered by
68
(a+b) = 2
cube both side
(a+b)³ = (2)³
a³ + b³ + 3ab(a+b) = 8
a³ + b³ + 3ab(2). = 8
a³ + b³ + 6ab. = 8
a³ + b³ + 6ab - 8. = 0
so the value of a³+b³+6ab -8. is. 0
cube both side
(a+b)³ = (2)³
a³ + b³ + 3ab(a+b) = 8
a³ + b³ + 3ab(2). = 8
a³ + b³ + 6ab. = 8
a³ + b³ + 6ab - 8. = 0
so the value of a³+b³+6ab -8. is. 0
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