Question

Find the value of a3+b3 - abc, given that a=3,b=2,&c=1​

Answer 1

Answer:

29

$({3})^{3} + ({2})^{3} - 3 \times 2 \times 1 = 29$

Hope it helps :)

Answer 2

Answer:

a3 +b3-abc

=(3*3*3)+(2*2*2)-(3*2*1)

=27+8-6

=29

a3+b3-abc=29