Question

Find the value of a3+b3+c3-3abc/ab+bc+ca-a2-b2-c2, when a=-5,5=-6,c=10​

Answer 1

Answer:

5×3+6×3+10×3-3×5×6×10=calculate it separateley. you will get the answer. answer will be 15+18+30-900=63-900 =answer will be 837.

please mark me as brainleast

Answer 2

$\large\blue{{\mathtt{Question:-}}}$

$\boxed{\orange{\frac{{a}^{3}+{b}^{3}+{c}^{3}-3abc}{ab+bc+ca-{a}^{2}-{b}^{2}-{c}^{2}}}}$

$\blue{\mathbb{Given:-}}$

$\mathtt\orange{a=-5, \: b=-6, \: c=10}$

$\mathtt\blue{Solution:-}$

$\large{\mathtt{\orange{\frac{{a}^{3}+{b}^{3}+{c}^{3}-3abc}{ab+bc+ca-{a}^{2}-{b}^{2}-{c}^{2}}}}}$

$\large\mathtt\orange{\frac{{-5}^{3}+{-6}^{3}+{10}^{3}-3\times-5\times-6\times10}{-5\times-6+-6\times10+10\times-5-{-5}^{2}-{-6}^{2}-{10}^{2}} }$

$\large \mathtt\orange{\frac{ - 125 + - 216 + 1000 - 900}{30 + - 60 + - 50 - 25 - 36 - 100} }$

$\large\mathtt \orange{\frac{ - 241}{ - 41} }$

$\large \mathtt \orange{5.87}$