Question

find the value of a3-b3+c3+3abc if a+C=b​

Answer 1

Answer:First we find the value of a

2

+b

2

+c

2

a

2

+b

2

+c

2

=(a+b+c)

2

−2(ab+bc+ca)=8

2

−2×19=64−38=26

∴a

3

+b

3

+c

3

−3abc=(a+b+c)(a

2

+b

2

+c

2

−ab−bc−ca)=(8)(26−19)=8×7=56

Step-by-step explanation:

Answer 2

Answer:

(a+c) ³=b³

a³+c³+3ac(a+c) =b³

a³+c³+3acb=b³

a³-b³+c³= -3abc