Question

find the value of a3+b3+c3-3abc when a=225 ,b=226,c=227

Answer 1

we know that a^3+b^3+c^3-3abc= (a+b+c) 1/2{ (a-b)^2+(b-c)^2+(c-a)^2}

On substituting the values in the formula,

(225 + 236 + 227) * 1/2 (225-236)^2 + (236-227)^2 + (227-225)^2)

= 2034

Answer 2

:) Heya Yash is here for help you :)

See my all steps :)

(a)³+(b) ³+(c)³-3abc

a=225

b=226

c=227

=(225)³+(226)³+(227)³-3.(225).(226).(227)

=(675)+(708)+(681)-(36161100)

= (- 3614036)

Hope this is helpful for u :)

Thanks :)