find the value of a³+b³+c³-3abc where a =1 , b =2 and c = -1
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Step-by-step explanation:
By putting the given values in the given equation we get :—
(1)³ + (2)³ + (-1)³ - 3(1 × 2 × -1)
= [(1 × 1 × 1) + (2 × 2 ×2) + (-1 × -1 × -1)] - 3 × (-2)
= 1 + 8 + (-1) - (-6)
= 8 + 6
= 14
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