Find the value of a³+b³, using apparopriate Identitywhen a+b=6, ab=7
(a) 45
(b) 90
(c) 91
(d) 98
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Answer:
(b) 90
step by step explaination:
63= (a+b)3 =a3 + 3a2b + 3ab2+b3 = (a3+b3) + 3ab(a+b)
so rearranging,
a3+b3 = 63−3 (7)(6)= 90
that's it!!!
please mark it as brainliest!!!
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