Question

find the value of a30-a20 for the AP 4, 7, 10

Answer 1

Answer:given AP 4,7,10

a=4, a2=7

d=a2-a1

d=7-4

d=3

an=a+[n-1]d

a30=4+[30-1]3

      =4+29×3

     =4+87

      =91

a20 =a+[n-1]d

       =4+[20-1]3

       =4+19×3

        =61

Step-by-step explanation:

Answer 2

The value of $a_{30}-a_{20}=30$

Step-by-step explanation:

Arithmetic progression :It is a sequence of numbers such that the difference between the consecutive terms is constant.

Formula of nth term of AP = $a_n=a+(n-1)d$

$a_n=nth term$

a= first term

n = No. of term

d = common difference

AP : 4, 7, 10...

First term = a = 4

Common difference = d= 7-4=10-7 =3

Substitute the value in the given formula and n = 30

So,$a_{30}=4+(30-1)3=91$

Substitute the value in the given formula and n = 20

So,$a_{20}=4+(20-1)(3)=61$

So,$a_{30}-a_{20}=91-61=30$

Hence the value of $a_{30}-a_{20}=30$

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Which term of the AP 10, 7, 4 is -41

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