Math, asked by muskaan, 13 hours ago

find the value of (ab+bc)(ab-bc)+(bc+ca)(bc-ca)+(ca+ab)(ca-ab)

Answers

Answered by 129807h

0

Answer:

0

Step-by-step explanation:

The answer is 0 when we cancel

1) ab+bc and ab-bc

2) bc+ca and bc-ca

3) ca+ab and ca-ab

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