Find the value of ab+bc+ ac when, a+b+c=10 and a2 +b2 +c2 =20
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Answer:
40
Step-by-step explanation:
let ab+bc+ac = X
a² + b² + c² = (a + b + c)² - 2ab - 2bc - 2ca
a² + b² + c² = (a + b + c)² - 2(ab + bc + ca)
20 = 10² - 2X
2x = 100 - 20
2x = 80
x = 80÷2
X = 40
thus, ab+bc+ca = 40
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