Find the value of ab+bc+ac, when a+b+c=l0 and a²+b²+c²=20
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We know that (a+b+c)^2=(a^2 +b^2 +c^2) +2(ab+bc+ca)—- -[1]
By Substituting the given values in [1],
(a+b+c)^2=20+2*40 = 20+80=100
(a+b+c)^2=100—»a+b+c=(+or-)10.
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