Find the value of ab + bc + ac,
where a + b + c =10 and
a² +b² +c² = 20
Answers
Answered by
1
Answer:
We know, (a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ca
(10)
2
=36+2(ab+bc+ca)
100−36=2(ab+bc+ca)
2(ab+bc+ca)=64
(ab+bc+ca)=32
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