Find the value of ab+bc+ca if a+b+c =27 and a² +b²+c²=105
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Use the identity,
(a+b+c)^2=a^2+b^2+c^2+2*(ab+bc+ca)
As:
2*(ab+bc+ca)=2×92=184
And,
a^2+b^2+c^2=105
Therefore,
(a+b+c)^2=105+184=289
Now taking square root of both sides,
a+b+c=17
Hence,17 is the answer.
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