Find the value of ab+bc+ca,if a+b+c =9 and a2 +b2 +C2 =35
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(a+b+c) ^2= a2+b2+c2+2(ab+bc+CA)
(9) ^2=35+2(ab+bc+ac)
81-35 = 2 (ab+bc+ca)
ab+bc+ca = (46÷2)
ab+bc+ca = 23
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