Find the value of ab when a³ - b³ = 5 and a -b = 5
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Using the formula (a-b)³
(a-b)³-a³-b³-3ab(a-b)
5³=a³-b³-3×5(5)
125=a³-b³-15×5
125=a³-b³-75
a³-b³=-75-125
a³-b³=-200
Answered by
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Answer:
Using the formula a³-b³ = 5
•(a-b)³- á³-b³-3ab(a-b)
=>5³=à³-b³-3×5(5)
=>125=a³-b³-75
=>a³-b³=-75-125
a³-b³= (-200)
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