find the value of ac in triangle abc when ab =3cm angle b=90degree
c=30degree
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Answer:
abc is a right triangle
sin30=Ab/ac
1/2=3/ac
ac=2×3
ac=6
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Answer
Angle B=90°
Angle A=30°
Angle C=60°__(remaining angle of triangle)
side opposite to 30° =1/2×hypotenuse
BC=1/2×AC
1/2×10
=5 cm
side opposite to 60° = √3/2×hypotenuse
AB =√3/2×AC
=√3/2 × 10
=5√3 was cm
Ans. side BC= 4cm. side AB =5√3 cm.
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