find the value of acceleration due to gravity at the surface of moon whose mass is 7.4 × 10^22kg and its radious is 1.75 × 10^6 m.
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62
Acceleration due to Gravity =g
= G M/R^2
= (6.67×10^-11×7.4×10^22)/ 1.75×10^6×1.75×10^6
= (6.67 × 7.4/1.75×1.75) × 10^-1
= 49.358/30.625
= 1.61 Newton
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= G M/R^2
= (6.67×10^-11×7.4×10^22)/ 1.75×10^6×1.75×10^6
= (6.67 × 7.4/1.75×1.75) × 10^-1
= 49.358/30.625
= 1.61 Newton
hope it helped,
plzzz mark as brainliest ......!
Diksha123:
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10
Mass of moon is, M = 7.31 × 1022 kg
Radius of moon is, R = 1.7 × 106 m
So, acceleration due to gravity of moon is, gm = GM/R2
=> gm = (6.67 × 10-11)(7.31 × 1022)/(1.7 × 106)2
=> gm = 1.68 m/s2
Radius of moon is, R = 1.7 × 106 m
So, acceleration due to gravity of moon is, gm = GM/R2
=> gm = (6.67 × 10-11)(7.31 × 1022)/(1.7 × 106)2
=> gm = 1.68 m/s2
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