Question

Find the value of

acube + asquareb + absquare + bcube at a = 1 and b = – 2

Answer 1

Answer:

a cube= 1³ = 1

b cube = (-2)³ = -8

a²×b = 1²×(-2) = -2

(a×b)² ={1×(-2)}² = {-2}² = 4

hence according to question now we get

1+ (-2) + 4 + (-8) = 1-2+4-8

Using BODMAS, we will solve the digit with addition sign first

= 1-2-4

= 1-6

= -5

Answer 2

Answer:

-5

Step-by-step explanation:

a³+a²b+ab²+b³

while,

a=1

b=-2

then,

(1)³+(1)²(-2)+(1)(-2)²+(-2)³

1+(-2)+4+(-8)

1-2+4-8

-5 is the answer