find the value of alpha^2+beta^2 for the polynomial x^2-7x+10
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Answer: 49.
Step-by-step explanation:
Given p(x) = x²-7x+10
Solving the equation by splitting the middle term method we get,
x²-5x-2x+10
x(x-5)-2(x-5)
(x-2)(x-5)
x = 2 and x=5
Therefore,
α = 2
β = 5
Now,
According to question, we've to find,
(α+β)² = (2+5)²
= (7)²
= 49
rajveerSinghkanawat:
oh
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