Question

Find the value of Δ and k, if the roots of the quadratic equation

2x² - 6x + k = 0 are real and equal​

Answer 1

Answer:

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Answer 2

Given :   quadratic equation

2x² - 6x + k = 0

Roots are real and equal​

To Find : value of Δ and k

Solution:

Quadratic equation is of the form ax²+bx+c=0  where a  , b and c are real also  a≠0.

D =  b²-4ac is called discriminant.

D >0 roots are real and distinct

D =0 roots are real and equal

D < 0 roots are imaginary ( not real ) and different

Roots are real and equal​

Hence Δ = D  = 0

Δ = D =  b²-4ac is called discriminant

2x² - 6x + k = 0

a = 2

b = - 6

c = k

(-6)² - 4(2)(k)  = 0

=> 36 - 8k = 0

=> 9 - 2k = 0

=> 2k = 9

=> k = 9/2

Value of k is 9/2

value of Δ = 0

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