find the value of angle A if in triangle abc a b barabar BC and Angle B 90
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Answer:
Angle A=45°
Step-by-step explanation:
In the question AB is equal to BC.
So, this is an isosceles triangle with Angles A and C as it's base Angles.
As, we know that the base Angles of an isosceles triangle are always same.
angleA=angleC
AngleB=90°,angle a+ angle c =180-90°=90°
angle a=(90/2)°=45°
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