find the value of angle A if in triangle abc , AB=BC and angle B=90
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Given= AB= BC
If sides are equal then the adjacent angles are also equal... So, Angle A = Angle C
Hence, In traingle ABC,
B= 90°
Angle A + Angle B+ Angle C= 180°
(Sum of angles of traingle is 180°)
Since, Angle A = Angle C
So,
Angle A + Angle B+ Angle A= 180°
2(angle A) = (180-90)°
2(Angle A) = 90°
So, Angle A = 45°
MARK ME AS BRAINLIEST PLZZ!!
HOPE TO HELP YOU!!
If sides are equal then the adjacent angles are also equal... So, Angle A = Angle C
Hence, In traingle ABC,
B= 90°
Angle A + Angle B+ Angle C= 180°
(Sum of angles of traingle is 180°)
Since, Angle A = Angle C
So,
Angle A + Angle B+ Angle A= 180°
2(angle A) = (180-90)°
2(Angle A) = 90°
So, Angle A = 45°
MARK ME AS BRAINLIEST PLZZ!!
HOPE TO HELP YOU!!
yAshay11:
u are right and i was wrong
Answered by
2
hey this is a very easy question
it is given that in a triangle ABC
AB=BC
and angle B= 90°(angle opposite to equal side)
so angle A =B=90°
now ,in triangle ABC angle A+B+C = 180°
angle 90°+90°+A =180°
180+a= 180
a = 0°
it is given that in a triangle ABC
AB=BC
and angle B= 90°(angle opposite to equal side)
so angle A =B=90°
now ,in triangle ABC angle A+B+C = 180°
angle 90°+90°+A =180°
180+a= 180
a = 0°
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