Question

find the value of angle AOB in the following figure......


WITH EXPLANATION......​

Answer 1

Answer:

${77}^{0}$

Step-by-step explanation:

in the given figure

$< cob = < dob = {145}^{0}$

so we can say that,

$< doa + < aob = {145}^{0}$

${68}^{0} + < aob = {145}^{0}$

$< aob = {145}^{0} - {68}^{0}$

$< aob = {77}^{0}$