find the value of angle AOD.
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90degree is the answer angle aod is 90 degree
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AB is a chord of a circle with centre O AB is produced to C such that BO = BC
CO is joined and produced to meet the circle at D
We shall prove x∘=3y∘
We have
BC=OB
∠OCB=∠BOC=y∘
[Angles opposite to equal sides are equal ]
∠OBA=∠BOC+∠OCB
[Ext angle of a △ is equal to the sum of the opposite interior angles ]
⇒∠OBC=y∘+y∘=2y∘
OA=OB...[Radii of the same circle ]
∠OAB=∠OBA....[Angles opp. To equal sides of a △]
=2y∘
∠AOD=∠OAC+∠OCA
=2y∘+y∘
=3y∘ [Exterior angle - Sum of opposite interrior angles]
⇒x∘=3y∘
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