Find the value of angle BCD
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<BDC+<BAC=180
<BDC=180-60. (AS IT IS AN EQUILATERAL TRIANGLE)
<BDC=120~~~(i)
Now,in triangle BDC
BD=DC,, SO <DBC=<DCB
Also sum of angles in a triangle =180
<BDC+<DCB+<DBC=180
2<DCB=180-120. (from i)
<DCB=30
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