Find the value of angle BOC ,if points A,Oand B are collinear
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Answered by
178
As A, O, B are collinear
So Angle(AOB) =180
Also AOB=BOC+DOC+AOD=180
x+5+4x-25+x-10=180
6x-30=180
6x=210
x=210/6=35
Angle BOC=x+5=35+5=40
Hope it helps
If yes then plz mark brainliest
So Angle(AOB) =180
Also AOB=BOC+DOC+AOD=180
x+5+4x-25+x-10=180
6x-30=180
6x=210
x=210/6=35
Angle BOC=x+5=35+5=40
Hope it helps
If yes then plz mark brainliest
Answered by
17
Answer:sup
Step-by-step explanation: x = 180
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