Find the value of angle 'x'.
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Step-by-step explanation:
in triangle ABC,
<C = 50°+30° = 80° ( given)
<B = 60°+20°=80° (given )
<A= ?
Now , <A + <B + <C = 180 ° ( angle sum property of ∆)
<A + 80° + 80° = 180°
<A + 160°=180°
<A = 180 ° -160°
<A = 20 °
Now , In ∆AEB ,
<A + <B+ <E = 180° ( angle sum property of triangle )
20° + 20° +<E = 180°
40° + < E = 180°
<E = 180° -40°
<E = 140°
now , in ∆ BCE
<B + < C + < E= 180° ( angle sun property of triangle )
80°+ 80°+ <E =180°
160° +<E = 180°
<E= 180°- 160°
<E= 20°
but , we know , <CEB = < FBE (alternate angles )
similarly , < x = <CBE ( alternate angles )
but , <CBE = 60°
hence , the value of. <x = 60°
therefore , correct answer is 60°
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