Math, asked by juneedmahboob, 1 month ago


Find the value of atb where A = x² + x + 1, B = x² -x + 1​

Answers

Answered by zoyashaikh151080
0

Answer:

n ∆ABC, BC = 1, sin A/2 =X1, sin B/2 =X2, cosA/2=X3,

cosB/2=X4 with

(X1/X2)

{x1 \div x2}^{2007 } - {x3 \div x4}^{2006}x1÷x22007−x3÷x42006

1 : length of side AC =

2: if <C=90,then area of ∆ABC=

Answered by rastogisantosh
0

Answer:

Let x1 = [1 3] be a solution of Ax = [1] [0] and x2 = [−1] [2] a solution of Ax = [0] [1] . a. Find a solution of Ax = [ −3 6 ] . b. Find a solution of Ax = [ b1 b2 ] for arbitrary values of b1 and b2. 3. If x1 and x2 are solutions of Ax = b, what equation does x1 + x2 satisfy? 4. Explain why a system of equations Ax = b cannot have exactly two distinct solutions.

Step-by-step explanation:

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