Math, asked by rohinigirhe89, 4 days ago

find the value of b^2-4ac if a=3, b=16 and c=9​

Answers

Answered by Roshan393
0

Answer:

9

Step-by-step explanation:

b²-4ac

b²-4aca=3,b=9 and c=6

b²-4aca=3,b=9 and c=6b²-4ac=9²-4×3×6

b²-4aca=3,b=9 and c=6b²-4ac=9²-4×3×6=81-72

b²-4aca=3,b=9 and c=6b²-4ac=9²-4×3×6=81-72=9

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