find the value of b^2-4ac if a=3, b=16 and c=9
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Answer:
9
Step-by-step explanation:
b²-4ac
b²-4aca=3,b=9 and c=6
b²-4aca=3,b=9 and c=6b²-4ac=9²-4×3×6
b²-4aca=3,b=9 and c=6b²-4ac=9²-4×3×6=81-72
b²-4aca=3,b=9 and c=6b²-4ac=9²-4×3×6=81-72=9
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