Question

Find the value of b^2 x^2+a^2 y^2-a^2 b^2, where x= a cos theta and y=b sin theta

Answer 1

the value is 0 b square (a cos theeta) ka whole square + a square (b sin theeta) ka whole square - a square b square, b square a square cos square theeta + a square b square sin square theeta - a square b square, we take common a square b square ( cos square theeta + sin square theeta)-a square b square, a square b square (1)-a square b square, 0 Answer