Question

find the value of (b-7)²​

Answer 1

Answer

(b-7)²​

= by the law [a-b]^2=a^2-2ab+b^2

thus

[b-7]^2=b^2-2[b][7]+7^2

           =b^2-14b+49

Answer 2

Answer:

by the law

(A-B)^2= A sq. + B sq. -2AB

According to question,

(b-7)^2= b^2+ 49 - 14b