Math, asked by HelenSaziine, 1 day ago

find the value of b for the quadratic equation bx (x_1)+7=0 so that it has two equal roots. ​

Answers

Answered by pushkarkoli76
0

Answer:

Step-by-step explanation:

Px(x-3) + 9 = 0

px2-3px+9=0

a=p , b=-3p , c=9

b2-4ac= (-3p)2-4(p)(9)

=9p2-36p

for having equal roots

b2-4ac = 9p2-36p = 0

9p2-36p = 0

9p(p-4) = 0

9p=0 (or) p-4=0

p=0(rejected) or p=4

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