Question

find the value of b if 3m^2 +2m-b =12 at m= 0​

Answer 1

Answer:

(3*0)^2+2*0-b = 12

0+0-b=12

b=-12

Answer 2

Answer:

given

3m^2+2m-b=12

then

m=0

sub m=0 in equation

we get

o+0-b=12

therefore -b=12

Adding (-) on both sides -(-b)=-12

b=-12