Question

find the value of b ' if alpha and 1/alpha are the zeroes of polynomial ax square +bx+c​

Answer 1

Answer:

ax

2

+bx+c=0

α+β=−

a

b

αβ=

a

c

(α+β)

2

=

a

2

b

2

(α−β)

2

=(α+β)

2

−4αβ

=

a

2

b

2

−

a

4c

=

a

2

b

2

−4ac

α−β=

a

b

2

−4ac

α

2

−β

2

=(α+β)(α−β)=

a

−b

(

a

b

2

−4ac

)

=

a

2

−b

b

2

−4ac