Question

Find the value of b if x-1 is a factor of (x)2+bx-3

Answer 1

if x-1 is a factor then x=1

1+b-3=0

b=2

Answer 2

Hope u like my process
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=> If (x-1) is a factor of f(x) =x²+ bx - 3,

Then, if x = 1, the f(x) = 0

So,

$= > \bf \: {x}^{2} + bx - 3 = 0 \\ \\ or. \: \: {1 }^{2} + b(1) - 3 = 0 \\ \\ or. \bf \: \: \: b = 3 - 1 = 2$
So, b = 2

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