Question

.Find the value of b if x³ -bx²+3bx-b if it is exactly divisible by (x-3)​

Answer 1

Answer:

Step-by-step explanation:

first find x from x-3=0

x= 3

now if x-3 is factor , when we put x=3 in given cubic it will become zero i.e

$(3)^3-b(3)^2+3b(3)-b=0\\\\27-9b+9b-b=0\\\\27-b=0\\\\b=27$

Answer 2

Answer:

Step-by-step explanation: