Question

Find the value of b in each case, if :

(i) 9b = 76^2 – 67^2

(ii) pqb = (3p + q)^2 – (3p – q)^2

pls quick

Answer 1

Step-by-step explanation:

first part

-

9b=76^2-67^2

(a-b=(a+b)(a-b))by identity

9b=(76+67)(76-67)

9b=(143)(1)

9b=143

b=143/9

b=15.88

b=15.9