Question

Find the value of b^x^ + a^y^-a^b^ where x =a cos theta . Y= b sin theta.

Answer 1

this is your answer... check it..

Answer 2

Here is ur answer!!

${a}^{2} {b}^{2} {cos}^{2} o \: + {a}^{2} {b}^{2} {sin}^{2} o \: - {a}^{2} {b}^{2} \\ \\ {a}^{2} {b}^{2} ({cos}^{2} o + {sin}^{2} o ) - {a}^{2} {b}^{2} \\ \\ {a}^{2} {b}^{2} - {a}^{2} {b}^{2} \\ \\ = 0 \:$
Hope it helps.

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