find the value of b²-4ac for the quadratic equation x²+10x+2 =0
Answers
Answered by
1
Answer:
Step-by-step explanation:
ax
2
+bx+c=0
For roots, D≡b
2
−4ac
and given that b
2
−4ac=0
⇒D=0
SO, equation will have only one root as,
x=
2(a)
−b±
b
2
−4ac
x=
2a
−b±0
x=
2a
−b
Only one real root.
Answered by
3
Step-by-step explanation:
b=10
a=1
c=2
b²-4ac=100-4*1*2=100-8=92
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