Find the value of b2 - 4ac of quadratic equation m² - 14m + 13 = 0
Answers
The first term is, m2 its coefficient is 1 .
The middle term is, -14m its coefficient is -14 .
The last term, "the constant", is +13
Step-1 : Multiply the coefficient of the first term by the constant 1 • 13 = 13
Step-2 : Find two factors of 13 whose sum equals the coefficient of the middle term, which is -14 .
-13 + -1 = -14 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -13 and -1
m2 - 13m - 1m - 13
Step-4 : Add up the first 2 terms, pulling out like factors :
m • (m-13)
Add up the last 2 terms, pulling out common factors :
1 • (m-13)
Step-5 : Add up the four terms of step 4 :
(m-1) • (m-13)
Which is the desired factorization
Answer:
m^2-14m+13=0
compairing to equation ax^2+bx+c=0
a=1
b= -14
c=13
b^2-4ac
=(-14)^2-4.1.13
=196-52
=144