Find the value of below algebriac expression for x=2,y=-1 and z=2 i) 4x2−3y2+5z2 ii) 1−4x(yz+3xy)
Answers
Answered by
1
Answer:
1.42 2. 65
Step-by-step explanation:
1. 4×2×2 -3×-1×2 +5×2×2=16+6+20=42
2. 1- 4×2(-1×2 +3×2×-1) = 1- 8( -2+-6)
= 1-8×-8
= 1- -64=65
Similar questions