find the value of boc if point a,o,b are collinear
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∠AOD,∠DOC,∠BOC are supplementary angles
⟹∠AOD+∠DOC+∠BOC=180
⟹(x−10)
+(4x−25)
+(x+5)
=180
⟹(6x−30)
=180
⟹6x−30=180
⟹6x=210
⟹x=
6
210
⟹x=35
∠BOC=(x+5)
=(35+5)
=40
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