Find the value of C for which the quadratic equation,
4x² -2 (C+1) x + (x+1)= 0 has equal roots.
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a=4, b= -2c-1 c=1
b^2-4ac=0
(-2c-1)^2 -4(4)(1)=0
4c^2+1+4c-16=0
4c^2+4c-15=0
4c^2+10c-6c-15=0
2c(2c+5)-3(2c+5)=0
(2c-3)(2c+5)=0
c=3/2 or c= -5/2
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