Question

find the value of c if the equation x square-2(c+1)x+c square =0 has real and equal root​

Answer 1

Step-by-step explanation:

Since, the roots are real and equal, D=0

D=

b

2

−4ac=0

(−2(c+1))

2

−4c

2

=0

4(c

2

+2c+1)−4c

2

=0

8c+4=0

∴c=

2

−1