Question

find the value of c if the line 2x+3y+c =0 passes through the origin​

Answer 1

Step-by-step explanation:

The line 2x+3y+c = 0 intercepts the x-axis where y = 0, so y = -(c/3). ow the ares of the triangle so formed = xy/2 = (-c/2)(-c/3)/2 = c^2/12, So if the area is to 27 sq units then c^2 = 12*27, or c = 18. Hence c = 18.

Answer 2

Since it passes through origin (x, y)=(0,0)

Put the value of X and y in equation

2×0+3×0+c=0

therefore c=0